Question

the position of a certain particle is described by s=4t³+3t²+5 where s is in meters and t is in seconds. determine the time t and acceleration a when v=0. Consider the positive values of t only​

Answer 1

Explanation:

Given,

s = 4t³+3t²+5

v = ds/dt = 12t²+6t

a = dv/dt = 24t+6

Here, when v = 0,

12t²+6t = 0

→ t = 0 or -1/2

As t can't be < 0, t = 0s

By first kinematic equation,

v = u+at → 0 = 0+a(0) → a€R

In this case, the acceleration of particle does not depend on its velocity