Question

the position of a moving particle at time t is given as x=6t+10t+2t^2.Find it velocity at time t=2sec

Answer 1

x=6t+10t+2t^2 at t=2 the velocity is x=6*2+10*2+2*2^2 =>x=40

Answer 2

GIVEN,

The position of a moving particle at time t is given as $x=6t+10t+2t^2$.

TO FIND,

The velocity of moving particle when time is 2 seconds.

SOLUTION,

As we know, the position of the moving particle is given by the equation

$x=6t+10t+2t^2$.

$x=16t+2t^2$

We know that if we differentiate the equation of position with respect to time, we get the equation of velocity.

After differentiating we get,

$v=4t+16$

Putting the value of t = 2 seconds,

$v= 4*2 +16$

$v=8+16$

$v=24$unit/s

Hence if the position of a moving particle at time t is given as $x=6t+10t+2t^2$. The velocity at time t=2 sec is 24 units/sec.