Question

The Position of a particle along the x-axis is given by x=3t3-7t where x in meters and t in

seconds. What is the average velocity of the particle during the interval from t=2sec to t=5sec?​

Answer 1

Explanation:

average velocity = X(f) - X(I) / t(f) - t(I)

X(I), at t = 2s is equal to 3 (2)³ - 7 x 2 = 24 -14 = 10m

X (f) ,at t = 5s is equal to 3 (5)³ - 7 x 5 = 3 x 125 - 35 = 375 - 35 = 340m

average velocity = (340 - 10) / (5 - 2)

= 330 /3 = 110m/s.