Question

The position of a particle at any instant is given by x=8t2

-3t3

, calculate
Instantaneous acceleration at t=2.0s
urgent​

Answer 1

Explanation:

s=8t²-3t³

ds/dt= velocity= d(8t²-3t³)/dt

velocity= 16t-9t²

and acceleration a= d(velocity)/dt

a= d(16t-9t²)/dt

a=16-18t

therefore at 2.0s

a=16-18×2

a= -20ms-²

it means that the body is retarding with a retardation of 20ms-².

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