The position of a particle going along a straight line is x=50 metres at 10:30 a.m. and x=55 at 10:35 a.m. find the displacement between 10:30 a.m. and 10:35 a.m. how? explain your answer.
Answers
Answer:
1 m/min
Explanation:
a = (v-u)/t,
where v = 55m, u = 50m and t = 5min
a = (55-50) / 5
a = 5/5
a = 1m/min
plz m as brainliest
The displacement of the particle between 10:30 a.m. and 10:35 a.m will be 5m.
Given,
The position of a particle going along a straight line is x=50 meters at 10:30 a.m. and x=55 at 10:35 a.m.
To Find,
The displacement between 10:30 a.m. and 10:35 a.m.
Solution,
The position of the particle at 10.30 A.M was x = 50 m, and the position of the particle at 10.35 A.M was x = 55 m.
So, the total time taken by the particle to travel this distance will be 5 minutes.
Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude. It is represented as an arrow that points from the starting position to the final position.
So,
Displacement of the particle = 55-50 = 5m.
Hence, the displacement of the particle between 10:30 a.m. and 10:35 a.m will be 5m.
#SPJ3