Question

the position of a particle in x axis is given by x=t^3-3t^2+2t find the velocity if t=2 secs

Answer 1

Velocity=2^3-3(2)^2+2(2)

=8-36+4

=-24m/s

Answer 2

Answer:2m/s

Explanation:

Equation is x=t^3 - 3t^2 + 2t.

Velocity=dx/dt

Velocity=d (t^3-3t^2+2t) /dt

Velocity=d(t^3)/dt - d(3t^2)/dt

d(2t)/dt

Velocity=3×t^2-3×2×t^1 +2×t^0

Velocity=3t^2 - 6t^1 +2

If t=2second;

Velocity=3 (2)^2 - 6 (2) +2

Velocity=2m/s