Question

The position of a particle is expressed as
r = (4t^2i + 2tj) m, where t is time in second. Find the
velocity of the particle at t = 3 s.
(A) 24.08 m/s
(B) 20.04 m/s
(C) 27.06 m/s
(D) 32 m/s​

Answer 1

Answer:

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Answer 2

Answer:

The position of a particle is expressed as r=(4t^2i + 2tj) m, where t is time in secondGiven that,

Time t=2s

Position vector r=(t3i^+t2j^)m

Now, on differentiate of position vector

dtdr=(3t2i^+2tj^)

Now, at t=2s

The velocity is

v=12i^+4j^

Now, the magnitude of velocity

  v=(12)2+(4)2

 v=160

 v=12.6m/s

Hence, the velocity is 12.6 m/s