Question

The position of a particle is given by r = 3.0ti—2.0t²j+4.0km, where tis in seconds and the coefficients have the proper units for r to be in metres, Find the v and a of the particle? (b) What is the magnitude and direction of velocity of the particle at t = 2.0 s ?

Answer 1

Dear Student,
                         As given in the question, v(t)= drdt=ddt(3.0 t iˆ+2.0 t2 jˆ + 5.0 kˆ)               =3.0ddt(t)iˆ  + 2.0ddt(t2) jˆ +5.0ddt(1) kˆ               = 3.0 iˆ + 4.0 jˆ +0 k ˆ            [  because the differentiation of constant = 0]

Regards