Question

. The position of a particle is given by r=3t i+ 2t^2 j + 5k where t is in seconds and the
coefficients have the proper units forr to be in metres. (a Find y(t) and a(t) of the particle,
(b) Find the magnitude of v(t) at t=1s
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Answer 1

Explanation:

v=dr/dt

v=d(3ti+2t^2j+5k)/dt=3+4t+0

v=3+4t

v=3+4(1)=7m/s

a=dv/dt=d(3+4t)/dt

a=4+0=4m/s^2