Question

The position of a particle is given by r=4t^3i - 3t^2j + 4k . Find the magnitude of velocity of the object at t=2 seconds

Answer 1

Answer:

( 3t i + 2t2 j + 4k ) m. velocity v = dr/dt = ( 3 i + 4t j) m/s. acceleration a = dv/dt = 4j m/s2. at t=2 s, velocity v = (3 i + 8 j)