the position of a particle is given by r=i+j+k and momentum p=2j+3k, find the direction of angular momentum? A; i-3j+2k/1+(-3)+2 B; i-3j+2k C; 1+(-3)+2/i-3j+2k D; -i-3j-2k
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Answered by
0
Answer:
I don't understand your question
Answered by
0
Answer:
Given,
r
=
i
^
+2
j
^
−
k
^
P
=3
i
^
+4
j
^
−2
k
^
Angular momentum,
L
=
r
×
P
L
=(
i
^
+2
j
^
−
k
^
)×(3
i
^
+4
j
^
−2
k
^
)
L
=0
i
^
−
j
^
−2
k
^
Hence, The angular momentum is perpendicular to the X-axis.
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