The position of a particle is given by where t is in seconds and the coefficients have the
proper units for r to be in metres.
(a) Find v(t) and a(t) of the particle.
(b) Find the magnitude and direction of v(t) at t=1.0s.
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Answer:
(a)
v (t)=d r /dt
=3.0^ i −4.0t ^j
a (t)=d v (t)/dt
=−4.0 ^j
(b)
v (2) =3.0^ i −8.0 ^ j
v(2)=8.54m/s
∠v(2)=tan −1 (−8/3)=−69.44 ∘ with x axis
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