Question

The position of a particle is given by x = 6 + 18t + 9t^2 m.

What is its velocity and acceleration at (a) t = 2 s, (b) t = 5 s.​

Answer 1

Answer:

velocity at t=2 is 54 m/s

velocity at t=5 is 108 m/s

acceleration is constant i.e 18m/s

Explanation:

differentiating the given equation

velocity v=18+18t

at t=2 v=54

at t=5 v=108

differentiating the equation again

acceleration a=18

the acceleration is constant at t=2 and t=5

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