the position of a particle moving along the x axis is given by x =A +4Bt^3. it's velocity at t = 5secs is
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1
Answer:
Explanation:
ie=
a
t
2
+
b
t
4
The velocity is given by:
v
=
d
x
d
t
=
2
a
t
+
4
b
t
3
Acceleration is given by:
a
=
d
v
d
t
=
d
2
x
d
t
2
=
2
a
+
8
b
t
2
For the velocity to be maximum,
d
v
d
t
=
0
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