The position of a particle moving along x axis at time t is given by eqn t=underroot x+2 .Find the work done by the force in first four sec??
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Explanation:
we know, power = V²/R
Here , V is the potential difference
And R is the resistance of wire.
Given,
Resistance of wire per unit length = 2 Ω/m
Let length of wire is L
Then, resistance of wire = resistance of wire per unit length × length of wire
= 2L Ω
Power = 1kW = 1000 watt
Potential difference , V = 200V
∴ 1000 = (200)²/2L
1000 = 40000/2L
L = 20 m
Hence, length of wire is 2
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