The position of a particle moving along x-axis given by x=(-2t3+3t2+5)m.The acceleration of particle at the instant its velocity becomes zero
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Distance = Total Area of velocity time graph
= (0.5 × 2.5 × 2) + (0.5 × 2.5 × 1) + (5 × 1)
= 8.75 m
Displacement = +ve Area of vt graph - (-ve area of vt graph)
= [(0.5 × 2.5 × 2)] - [(0.5 × 2.5 × 1) + (5 × 1)]
= -3.75 m
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