The position of a particle moving along X-axis is given by :
* = At + 4 Bt^3
What is its velocity at t = 5 s?
Please Solve it Step by step....
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X = at + 4bt^3
V = dx/dt
V = a + 12bt^2
Put t = 5
V = a + 12(25)b
V = a + 300b
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