Physics, asked by legend4517, 4 months ago

The position of a particle moving along X-axis is given by :
* = At + 4 Bt^3
What is its velocity at t = 5 s?

Please Solve it Step by step....​

Answers

Answered by AionAbhishek
3

X = at + 4bt^3

V = dx/dt

V = a + 12bt^2

Put t = 5

V = a + 12(25)b

V = a + 300b

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