Question

the position of a particle moving along x-axis is given by x=10t-2t^2.Then time (t) at which it will momently come o rest is

Answer 1

x = 10t - 2t^2

v = dx/dt = 10 - 4t

It will come to rest when v = 0

0 = 10 - 4t

t = 10/4 = 2.5 s

It will come to rest after 2.5 seconds.