The Position of a particle moving along x axis is given by x=t^3+t^2+t+1 m find. (1) position of particle at t= 0 sec ,at 2 sec,at 3 sec,at 10 sec .
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Answer:
Given:
a=8.5
b=2.5
x=a+bt
2
dt
dx
=2bt
V
t=2
=
dt
dx
=2×2.5×2=10 ms
−1
Step-by-step explanation:
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