Physics, asked by AashitaShree, 11 months ago

The position of a particle moving along x-axis is
given by x = 10t - 2t2. Then the time (t) at which
it will momently come to rest is
(2) 2.5 s
(3) 5 s
(4) 10 s
(1) 0

Answers

Answered by mohan1508
2

When the object comes to rest ,

x = 0

Then

0 \:  =  \: 10t \:  -  \: 2t {}^{2}

t ^{2}  \:  =  \: 5t

Therefore

t = 5

Answer option (3) 5 sec

Hope this would help you.. Please use the right to report my answer if it is wrong.. Thank you ..


mohan1508: velocity is the derivative of displacement
mohan1508: therefore on derivating 10t + 2t^2 we get ..
mohan1508: ... 10 + 4t
mohan1508: sorry .. on derivating 10t - 2t^2 we get ...
mohan1508: 10 - 4t
mohan1508: hence velocity = 10 - 4t = 0
mohan1508: 10 = 4t
mohan1508: t = 2.5
mohan1508: Hope you understood
mohan1508: Thanks for correcting me ..
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