Physics, asked by krishnakabra334, 7 months ago

The position of a particle moving along x axis varies as
x(t)=2t² -3t+4m
where t is in seconds. The average velocity between t= 0 and t = 2s is

0.5 m/s
-1 mis
1 m/s
2 m/s

Answers

Answered by brainlyaryan12

2

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→ The position of a particle moving along x axis varies as

x(t)=2t² -3t+4m

where t is in seconds. The average velocity between t= 0 and t = 2s is

0.5 m/s

-1 mis

1 m/s

2 m/s

$<font color = lime>$

✪ $\huge{\green{\underline{\overline{\mathbf{Answer}}}}}$ ✪

⇒Given:

$x(t)=2t^2-3t+4$ m

⇒To Find:

Average velocity between-
t = 0s and t = 2s

⇒Solution:-

⇒ $\displaystyle \int\limits_{0}^{2} (2t^2-3t+4)\;dt$

⇒ $\bigg[2\times \big[\frac{t^{2+1}}{2+1}\big] -3\times \big[\frac{t^{1+1}}{1+1}\big]+4t\bigg]_{0}^{2}$

⇒ $\bigg[\frac{2t^3}{3}-\frac{3t^2}{2}+4t\bigg]_{0}^{2}$

⇒ $\bigg[\frac{2(2)^3}{3}-\frac{3(2)^2}{2}+4(2)\bigg] -\bigg[0-0+0\bigg]$

⇒ $\frac{16}{3}-6+8$

⇒ $5.{\bar{3}}+2$

⇒ $\huge{\pink{\overbrace{\underbrace{\purple{v=7.{\bar{3}}\:ms^{\tiny{-1}}}}}}}$

$<font color = cyan>$

≿━━━━━━━━━༺❀༻━━━━━━━━━≾

Formulas Used :-

$\int x^n\;dx$

$\Large{\blue{\bigg[\frac{x^{n+1}}{n+1}\bigg]}}$

≿━━━━━━━━━༺❀༻━━━━━━━━━≾

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