Physics, asked by krishnakabra334, 9 months ago

The position of a particle moving along x axis varies as
x(t)=2t² -3t+4m
where t is in seconds. The average velocity between t= 0 and t = 2s is

0.5 m/s
-1 mis
1 m/s
2 m/s​

Answers

Answered by brainlyaryan12
2

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→ The position of a particle moving along x axis varies as

x(t)=2t² -3t+4m

where t is in seconds. The average velocity between t= 0 and t = 2s is

0.5 m/s

-1 mis

1 m/s

2 m/s

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⇒Given:

  • x(t)=2t^2-3t+4 m

⇒To Find:

  • Average velocity between-
  • t = 0s and t = 2s

Solution:-

\displaystyle \int\limits_{0}^{2} (2t^2-3t+4)\;dt

\bigg[2\times \big[\frac{t^{2+1}}{2+1}\big] -3\times \big[\frac{t^{1+1}}{1+1}\big]+4t\bigg]_{0}^{2}

\bigg[\frac{2t^3}{3}-\frac{3t^2}{2}+4t\bigg]_{0}^{2}

\bigg[\frac{2(2)^3}{3}-\frac{3(2)^2}{2}+4(2)\bigg] -\bigg[0-0+0\bigg]

\frac{16}{3}-6+8

5.{\bar{3}}+2

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Formulas Used :-

\int x^n\;dx

  • \Large{\blue{\bigg[\frac{x^{n+1}}{n+1}\bigg]}}

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