The position of a particle moving in a straight line is described by the relation ,S=6+12t-2t^2. Here S in meter and the in seconds. The distance covered by in first 5 sec. is?
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Answer:
16m
Explanation:
t=5
substitute in the equation gives
s=6+12×5-2×25
s=6+60-50
s=6+10
s=16
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