the position of a particle moving in a straight line is given by X =3+4t+3t^2 where X is in metre and time is in seconds find the value of the following physical quantities of the particle at t = 2s..find (1) position (2) displacement (3)velocity (4) acceleration
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the particle at t=0 is X=3m
at t=2. X=23m (position)
so displacement is 23-3 = 20m
Velocity is d(X)/dx = 4+6t = 16 m/s
acceleration is d(V)/dx = 6m/s^2
at t=2. X=23m (position)
so displacement is 23-3 = 20m
Velocity is d(X)/dx = 4+6t = 16 m/s
acceleration is d(V)/dx = 6m/s^2
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