Question

The position of a particle moving in a straight line is given by x = 3 + 4t + 3t2, where x is in
metre and time is in second. Find the values of the following physical quantities for the particle
at t = 2s. (See Lesson- 2)
(i) Position
(ii) Displacement
(iii) Velocity
(iv) Acceleration

Answer 1

At t=2
(I)position
It will be x=23
(Il) displacement will be 23 meters
(iii) velocity will be 16m/s
(iv) acceleration will be 6m/s^2
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