Question

the position of a particle moving in a straight line is given by x=3+4t+3t, where x is in metre and time is in second. find the values of the following physical quantities for the particle at t=2s. i)position ii) displacement iii) velocity iv) acceleration

Answer 1

x = 3 + 4t + 3t

1) position = 3 + 4×2 + 3×2

= 3 + 8 + 6 = 17

2) Displacement = 3 + 4×2 + 3×2

= 17

3) Velocity = dx/dt

= d(3 +4t+3t)/dt

= 7

4) Acceleration = dv/dt

= d(7) / dt

= 0


Thanks