Question

The position of a particle moving on a straight line path is given by x = 12 + 18t + 19t². Its acceleration at any instant is ​

Answer 1

v = dx/dt and a = dv/dt

v = d/dt (12 + 18t + 19t²)

= 0 + 18 + 38t

a = d/dt (18 + 38t)

= 0 + 38 = 38 m/s²