Question

The position of a particle moving on a straight line path is given by x = 12 + 18t + 19t². Its acceleration at any instant is ​

Answer 1

x = 9t^2 + 18t + 12

velocity.v = dx/dt

dx/dt = 18t + 18

also , a = dv/dt

a = 18 m/s^2

Answer 2

Answer:

18ms-2 this is the answer