the position of a particle moving on straight line path is given by x= 12+18t+9t2 meter. its acceleration at t= 5s is
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x = 9t² + 18t + 12
velocity,v = dx/dt
dx/dt = 18t + 18
Also , a = dv/dt
a = 18m/s²
velocity,v = dx/dt
dx/dt = 18t + 18
Also , a = dv/dt
a = 18m/s²
Answered by
0
Answer:
Explanation:
X=9t^2+18t+12
T=5s
Now differentiate this value
X=9t+18
X=63ms-1
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