Question

the position of a particle moving on x axis is given as x=4t^3.find
1.average velocity in (i)first five second (ii) instantaneous velocity at t=5s
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Answer 1

Answer:

(i) 100 m/s

(ii) 300 m/s

Explanation:

X(t) = 4 t^3

(i) avg velocity = total displacement / total time

= { X(5) - X(0) } / (5 - 0)

= ( 4 × 5^3 - 0) / 5 = 100 m/s

(ii) v(t) = dX(t) / dt

= 12 t^2

v(5) = 12 × 5^2 = 300 m/s