The position of a particle of mass 1 kg changes with time which is given by the relation 8(t) = 318-2Vt, where t is in seconds. What will be the force experienced by the particle at time 2 sec ?
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Answered by
1
Answer:
Given, x=2t
3
+3
⇒dx=6t
2
⇒a=
dt
2
d
2
x
⇒a=12tAnd,Force=1×12t=12t
So, the word done in first two second =∫Fdx
⇒W=∫
0
2
72t
3
=288J
Explanation:
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Answered by
1
Solution
verified
Verified by Toppr
Given, x=2t
3
+3
⇒dx=6t
2
⇒a=
dt
2
d
2
x
⇒a=12tAnd,Force=1×12t=12t
So, the word done in first two second =∫Fdx
⇒W=∫
0
2
72t
3
=288J
verified
Verified by Toppr
Given, x=2t
3
+3
⇒dx=6t
2
⇒a=
dt
2
d
2
x
⇒a=12tAnd,Force=1×12t=12t
So, the word done in first two second =∫Fdx
⇒W=∫
0
2
72t
3
=288J
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