Question

the position of a particle varies with t as x=at^2-bt^3 where a= 6m/s2 and b= 3.5m/s3. Calculate the velocity at t = o and t = 4 sec

Answer 1

Explanation:

x=at^2-bt^3

value of a = 6and b = 3.5

velocity is derivative of x/t

which is 2at-3bt

after solving we will get

V= 0 at time 0sec

V=6 at time 4 sec