Question

The position of a particle varies with time t as
x = 3t^2 + 6t - 6. The average velocity of body in
first two seconds is
(1) 12 m/s
(2) 14 m/s
(3) 18 m/s
(4) 09 m/s​

Answer 1

x = 3t^2 + 6t - 6

dx/dt = d(3t^2 + 6t - 6)/dt

v = 6t + 6

At t = 2s

v = (6 × 2 + 6)/2

v = 18/2

v = 9 m/s

Answer 2

Answer:

(4) 09 m/s

v == 9 m/s

It is the answer go for it