Question

The position of a particle x depends on time t according to the relation x = (3 m/s) - (1 m/s^2)t^2. The speed
of the particle at t = 2 s is​

Answer 1

$dv=\frac{dx}{dt}\\dv= \frac{d(3-t^2)}{dt}\\dv=-2t$

At t=2,

-2(2)= -4 m/s