The position of a particular moving along x - axis at t= 3 sec is x= 6 m and t= 8 it is x= 21 m. What will be the average velocity of the particle in time period b/w 3 sec. and 8 sec.?
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Hi here's answer...
t1= 3 sec
d1= 6 m
then, S1 = d1/t1 = 6/3= 3
t2= 8
d2= 21
then, S2= d2/t2= 21/8
A. V. = total distance/ total time
then, step by step
explanation.......
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t1= 3 sec
d1= 6 m
then, S1 = d1/t1 = 6/3= 3
t2= 8
d2= 21
then, S2= d2/t2= 21/8
A. V. = total distance/ total time
then, step by step
explanation.......
❄❄❄❄❄❄❄❄❄
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