The position of a projectile launched from the origin at t=0 is given by r= 40 i^+50j^ at t=2secr→=(40i^+50t=2s. If the projectile was launched at an angle thetaθfrom the horizontal , then thetaθis
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2ux = 40 => 4x = 20
50 = 24y - 1/2 * 10 * 22 => 4y = 35
tan theta = uy / ux = 35 / 20 = 7 / 4
theta = tan -1 [ 7/4 ]
50 = 24y - 1/2 * 10 * 22 => 4y = 35
tan theta = uy / ux = 35 / 20 = 7 / 4
theta = tan -1 [ 7/4 ]
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