Question

the position of a stone dropped from rest from the top of a tower is given by x = 5t^2 what is the velocity of stone when it reaches ground? given height of tower 80m​

Answer 1

Answer:

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Answer 2

Explanation:

given,

position of the stone is given by x= 5t²

differentiating with respect to t it gives v= 10t

when it reaches the ground height is -80 m

so,

-80= -gt²/2

t= 4 sec

velocity at 4sec is 10(4)= 40 m/sec