Question

The position of an atom moving inside a cathode ray tube is given by the function f(t)=t^3-4t^2+3t
Where t is in seconds and f(t) is in meters.
Find the instantaneous velocity of the atom at t=2.5 seconds

Answer 1

Answer:

Given,

s=3t

3

5t

2

+2t

So displacement,

Instant velocity, v=

dt

ds

⇒v=

dt

d(3t

3

5t

2

+2t)

=9t

2

+10t+2.......1

If t=1s eqtn {1} becomes

v=9+10+2=21m/s