The position of an object changes from r = (2i^+j^) m to r = (4i^+3j^) m in 2s. Find its average velocity.
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Secondary SchoolPhysics15 points
The position of an object change from r= (2i+j) to r=(4i+3j) in 2s find average velocity
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Ask for details FollowReport bySrisasthaarangi5815 3 weeks ago
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anshsaxena1908Ambitious
First we need to determine what the displacement will be in this case.
We can determine the displacement using the distance formula studied in 10th.
distance between two points= 
In this case,
displacement= 
s=
s=
s=
Therefore, s= 
Now, average velocity= displacement/time
v=
Therefore,
v=
1
Secondary SchoolPhysics15 points
The position of an object change from r= (2i+j) to r=(4i+3j) in 2s find average velocity
Advertisement
Ask for details FollowReport bySrisasthaarangi5815 3 weeks ago
Answers
anshsaxena1908Ambitious
First we need to determine what the displacement will be in this case.
We can determine the displacement using the distance formula studied in 10th.
distance between two points= 
In this case,
displacement= 
s=
s=
s=
Therefore, s= 
Now, average velocity= displacement/time
v=
Therefore,
v=
vsg4737:
and one more thing
you just do what I do
yaa okay
Now, average velocity= displacement/time
v=in denominator 2 and up is
2 (2)1/2 Therefore,
v=-/2
v=in denominator 2 and up is
2 (2)1/2 Therefore,
v=-/2
done I gtg my mom saying sleep right now byee
okay
thanks once again
no problem
if u have any problem just ask
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Answered by
1
Answer:
Root 2
Explanation:
average velocity =
∆v/∆t= 2i+j - 4i + 3j/2
=i+j
v=√1^2+1^2
= √1+1
= √2.
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