Question

The position of an object changes with time as x = 2t – 5t2 + t3. The initial velocity of the object is (where x is in metre and t is in second)
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Answer 1

Your answer is given -:::

Given displacement x=5+3t+2t

2

Differentiating the above equation with respect to time t we get velocity of the body

v=

dt

dx

=3+4t

Now again differentiating the velocity with respect to time we get acceleration

a=

dt

dv

=4

Answer 2

Answer:

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• Given displacement x=5+3t+2t. 2. Differentiating the above equation with respect to time t we get velocity of the body.