The position of an object is given by x=Ax^3+Bx^2+C.Find the acceleration at t=3 sec.
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Distance is a function of time so can you, confirm the question as whether x=At
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d(x)/dx=3Ax^2+2Bx
d^2(x)/dz=6Ax+2B
ans is 18A+2B.
d^2(x)/dz=6Ax+2B
ans is 18A+2B.
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The answer is found in the attachment below:-
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