Question

the position of an object moving aling x axis is given by x= a+bt^2 where a=8.5m, b=2.5m/s^2 and t is measured in seconds.. what is the velocity at t=0 sec and t= 2sec .what is the average velocity between t=2sec and t=4sec​

Answer 1

Answer:

Position is given as x=a+bt

2

=8.5+2.5t

2

Position at t=2 s, x

2

=8.5+2.5(2)

2

=18.5 m

Position at t=4 s, x

1

=8.5+2.5(4)

2

=48.5 m

Displacement S=x

2

−x

1

=48.5−18.5=30 m

Time taken t=4−2=2 s

Average velocity V

avg

=

t

S

=

2

30

=15 m/s

Answered WANIIQRA

Answer 2

Answer:

nope

Explanation: