Question

The position of an object moving along x-axis is given by x (t)=3t^2 - 18t+10 m. Find :
1)
initial velocity of the particle.
2)time at which velocity becomes zero 3
3)
acceleration at t = 4s​

Answer 1

Answer:

I don't know answer sorry

Answer 2

Answer:

Explanation:

Given

$x(t)=3t^2-18t+10$

and we know velocity is given by

$\frac{\mathrm{d} x}{\mathrm{d} t}=6t-18$

v=6t-18

thus for initial velocity t=0

v=-18 m/s

negative indicate that velocity is in opposite direction

2)time at which velocity is zero

v=0

i.e.

6t-18=0

t=3 s

3) acceleration at t=4 s

$\frac{\mathrm{d^2} x}{\mathrm{d} t^2}=6$

$a=6 m/s^2$