Question

The position of an object moving along x-axis is given by x = a bt² where a = 8.5m , b = 2.5 ms-² and t is measured in seacond.what is it velocity at t= 0s and t= 2.0s . what is the average velocity between t= 2.0s and t= 4.0s​

Answer 1

Explanation:

The position of an object moving along x-axis is given by x = a + bt 2

, where a = 8.5 m and b = 2.5 m s −2

and t is measured in seconds. The averagevelocityof the object between t = 2 s and4s is

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Answer 2

Answer:

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Explanation:

Position is given as x=a+bt

2

=8.5+2.5t

2

Position at t=2 s, x

2

=8.5+2.5(2)

2

=18.5 m

Position at t=4 s, x

1

=8.5+2.5(4)

2

=48.5 m

Displacement S=x

2

−x

1

=48.5−18.5=30 m

Time taken t=4−2=2 s

Average velocity V

avg

=

t

S

=

2

30

=15 m/s.

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