Question

the position of an object moving along x axis is given by x= 5 + 10t2. the average velocity between t= 2s and 4s is​

Answer 1

Answer:

120 ms^-1

Explanation:

Let f(t)=5+10t^2

f(2 sec)=5+(10)2^2

=5+40

=45

f(4 sec)=5+(10)4^2

=5+160

=165

the average velocity between t= 2s and 4s is

f(4)-f(2)

=165-45

=120 ms^-1

Answer 2

Answer:

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Explanation:

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