Question

The position of an object moving along x axis is given by x=5+10t^2 . Then the average velocity between t=2s and 4s is :

a)40m/s
b)60m/s
c)80m/s
d)20m/s​

Answer 1

Answer:

80m/s please follow me please make a Brainlist answer

Answer 2

Answer :

The position of an object moving along x-axis is given by

• x = 5 + 10t²

We have to find the average velocity of object between t = 2s and 4s$.$

Instantaneous velocity is given by

• v = dx/dt

➜ v = d(5+10t²)/dt

➜ v = 0 + 20t

➜ v = 20t

Velocity at t = 2s :

➝ v = 20t

➝ v = 20(2)

➝ v = 40 m/s

Velocity at t = 4s :

➝ v = 20t

➝ v' = 20(4)

➝ v' = 80 m/s

• Average velocity :

➜ Vav = (v+v')/2

➜ Vav = (40+80)/2

➜ Vav = 120/2

➜ Vav = 60 m/s

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