Question

The position of an object moving along x- axis is given by x=8.5+2.5t^2.
a)what is its velocity at t=2.0s​

Answer 1

Answer:

v = 5t

v = 5(2) = 10 m/s

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Answer 2

Step-by-step explanation:

Position is given as   x=a+bt2=8.5+2.5t2

Position at t=2 s,  x2=8.5+2.5(2)2=18.5 m

Position at t=4 s,   x1=8.5+2.5(4)2=48.5 m

Displacement  S=x2−x1=48.5−18.5=30 m

Time taken  t=4−2=2 s

Average velocity  Vavg=tS=230=15 m/s