Physics, asked by ramakrushnabehera762, 1 month ago

The position of an object moving along x-axis is given by x=a+bt ^2 where a=8.5m, b=2.5m s^-2 and t is measured in second. what is its velocity at t=0 s and t=2.0 s. what is the average velocity between t=2.0 s and t=4.0 s ?​

Answers

Answered by singhyogendra559
1

Answer:

Position is given as x=a+bt

2

=8.5+2.5t

2

Position at t=2 s, x

2

=8.5+2.5(2)

2

=18.5 m

Position at t=4 s, x

1

=8.5+2.5(4)

2

=48.5 m

Displacement S=x

2

−x

1

=48.5−18.5=30 m

Time taken t=4−2=2 s

Average velocity V

avg

=

t

S

=

2

30

=15 m/s


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