The position of an object moving along x-axis is given by x(t)=4.5+3t² where t is measured in seconds. What is the average velocity between t=2 seconds and t=4 seconds? Answer upto o decimal.
Answers
Answer:
depository of an object moving along x axis in given by x where is mustard in second what is the average
Step-by-step explanation:
Given:-
The position of an object moving along x-axis is given by x(t)=4.5+3t^2 where t is measured in seconds.
To find:-
What is the average velocity between t=2 seconds and t=4 seconds? Answer upto o decimal.
Solution:-
The position of an object moving along x-axis = x(t)=4.5+3t^2
Where t is measured in seconds
The position of the object at t = 2 seconds
=>x(2)=4.5+3(2)^2
=>x(2)=4.5+3(4)
=>x(2)=4.5+12
=>x(2)=16.5
The position of the object at t= 4 seconds
=>x(4)=4.5+3(4)^2
=>x(4)=4.5+3(16)
=>x(4)=4.5+48
=>x(4)=52.5
The displacement of the object from 2 seconds to 4 seconds
=>Final position - Initial position
=>x(4)-x(2)
=>52.5-16.5
=>36 units
Now the object travel from 2 s to 4s = 4-2 = 2seconds
Time travelled by the object = 2 seconds
The average velocity between t=2 seconds and t=4 seconds
=>Average Velocity = Displacement/ change in time
=>36/2
=>18 units/seconds
If x is measured in meters then
Average velocity = 18 m/s
Answer:-
The average velocity between t=2 seconds and t=4 sec of the given object = 18 m/s
(if x ix measured in meters )
Used formulae:-
Average Velocity = Displacement/ change in time