the position of an object moving along x-axis is given by x is equal to a + b ka whole square where a is equal to 8.5 m b is equal to 2.5 M per second square and T is measured in seconds what is the velocity at t is equal to zero II and t is equal to 22 second? What is the average velocity between t is equal to 2 S and T is equal to 4 yes please please please tell me how to find the instantaneous velocity in this question only this question is for more and more clocks 100 points and whoever will give correct and quick answer will be worked as BRAINLIEST
Answers
Answered by
7
Hy sis, here's ur ans...
X = a + bt^2
v = 2bt
Velocity at t = 0 is 0
Velocity at t = 2s is = 2*2.5*2 = 10 m/s
At t = 2s
x = 8.5 + 2.5*2^2
x = 18.5m
At t = 4s
x = 8.5 + 2.5*4^2
x = 48.5m
Average velocity = (48.5 - 18.5) / 2 = 18m/s
: )
Hope it helped u...
X = a + bt^2
v = 2bt
Velocity at t = 0 is 0
Velocity at t = 2s is = 2*2.5*2 = 10 m/s
At t = 2s
x = 8.5 + 2.5*2^2
x = 18.5m
At t = 4s
x = 8.5 + 2.5*4^2
x = 48.5m
Average velocity = (48.5 - 18.5) / 2 = 18m/s
: )
Hope it helped u...
spine:
can u tell me how i can find instantaneous velocity
Answered by
2
hope it helps you and please please add to Brian list
Attachments:
Similar questions