Question

the position of an object moving along x-axis is given by x = 2+ 2.5^2, x is measured in metre and T is second what is the initial velocity of the particle. a)2 m s^-1. b) 9 m s-1. c) 4.5m s^-1. d) zero​

Answer 1

Answer:

(a) $v=2 ms^{-1}$

Explanation:

Please check the question published.

I'll assume the equation as:

$x= 2t+ 2.5t^{2}$

$\frac{dx}{dt } = 2+5t$

∴$v= 2+5t$

For initial velocity, take t=0

$v=2 ms^{-1}$

So, this gives your option (a)